- A.<img src="//img1.yqda.net/question-name/d0/d427e91dc772a4b6e2662f437f2414.png" width="45" height="33"/>
 - B.<img src="//img1.yqda.net/question-name/ed/50ac8f0f16dfe6e23e68376e842097.png" width="45" height="33"/>
 - C.<img src="//img1.yqda.net/question-name/f9/9e81dde80e8feeb4e7aad29064bdfd.png" width="44" height="24"/>
 - D.<img src="//img1.yqda.net/question-name/96/d07aba9cc69368d86e78c77b4e1896.png" width="44" height="24"/>
 
- A.<img src="//img1.yqda.net/question-name/93/0340a581cbae53304116963ac7859b.png" width="19" height="24"/>
 - B.<img src="//img1.yqda.net/question-name/8a/e7515a9d46eadfaeaf622652ec2b98.png" width="20" height="24"/>
 - C.<img src="//img1.yqda.net/question-name/13/dd801225836c47d5920972ecae7a60.png" width="19" height="24"/>
 - D.<img src="//img1.yqda.net/question-name/db/4ee354a3d62e68866435be458b82da.png" width="20" height="24"/>
 
- A.N(0,1/n)
 - B.N(0,1)
 - C.χ<sup>2</sup>(n)
 - D.t(n)
 
- A.0
 - B.1
 - C.3
 - D.4
 
- A.5
 - B.23
 - C.67
 - D.85
 
- A.0.2
 - B.0.25
 - C.0.3
 - D.0.5
 
- A.F(-∞)=0
 - B.F(+∞)=1
 - C.0≤F(x)≤1
 - D.F(x)是连续函数
 
- A.N(-1,3)
 - B.N(-1,9)
 - C.N(0,3)
 - D.N(1,9)
 
- A.0.008
 - B.0.488
 - C.0.512
 - D.0.992
 
- A.1
 - B.P(A)
 - C.P(B)
 - D.P(AB)
 
我

,其概率密度为f(x)。
,给定检验水平α,则拒绝H0的理由是( )



